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0x11 0x11
You'll get 0x12 0x12
Then,0x0A
AddressLo
AddressHi
ProgLengthLo
ProglengthHi
[program itself]
(may be 0x11 0x11 /0x12 0x12 handshake once again?)
0xAA
StartAddLo
StartAddHi
And here how to write it:ld bc,5000 loop: ld a,0 out (0FH),a in a,(0FH) bit 0,a jr nz, gotit dec bc ld a,b or c jnz loop
(here means we got no char in 5000 iterations)gotit: in a,(0DH)
Char in a
out (0DH),a